If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3t^2+14t+16=0
a = 3; b = 14; c = +16;
Δ = b2-4ac
Δ = 142-4·3·16
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*3}=\frac{-16}{6} =-2+2/3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*3}=\frac{-12}{6} =-2 $
| 22=11/12a | | 10=2/5w | | 49=4r+9 | | 5+-2n=91+1 | | 3(w-67)=12 | | 3+x+24=28x | | 0=3t^2+14t+16 | | 70x=75x^2 | | w/3-14=19 | | 16q+4q-11q-q-7q=12 | | -7(w-97)=70 | | 3–7x=24 | | 16q-4q-11q-q-7q=12 | | b+98=180 | | 2h+23=59 | | 1/2n+3=1/2(-n+14) | | 10h-2h-7h=3 | | -4g+16g-7g-5g+6g=-6 | | -23=3u=9-11u | | 2{x-6}+6=4x-4 | | 6(z+3)=90 | | 6x+2-4(x+1)=9x+2 | | 2h/5-7=63/10 | | 7(f-82)=91 | | 6j+5j-3j=8 | | 7q-4q-3q+q=13 | | 4(15)-y=15 | | 6y+2=60 | | 8-4(x+1)=16 | | 11b-10b-b+2b=12 | | 1. 8-4(x+1)=16 | | z/7+3=-29 |